Find the maximum and minimum value of y=1+2sinx respectively.
A
3,−1
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B
1,−3
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C
−1,−3
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D
−3,−1
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Solution
The correct option is A3,−1 Maximum value of sinx=1
Therefore maximum value of y is y=1+2(1)=3
Minimum value of sinx=−1
Therefore minimum value of y is y=1+2(−1)=−1