Find the maximum and minimum values, if any of the following function given by $h (x) = sin (2 x) + 5$

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Solution

$h (x) = sin (2 x) + 5$
We know that, $- 1 \leq sin θ \leq 1, \forall θ \in R$
Hence $h_{m a x} = 1 + 5 = 6$ and $h_{m i n} = - 1 + 5 = 4$

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