Question

Find the maximum and minimum values, in the following function.
$f\left(x\right)=|x+2|-1$ where x is a real number

• A. $\text{maximum = -1 and minimum = no value}$
• B. $\text{maximum = -2 and minimum = -1}$
• C. $\text{minimum = -1 and maximum = no value}$
• D. $\text{maximum = -1 and minimum = -2}$

Answer 1

The correct option is C $\text{minimum = -1 and maximum = no value}$

we know that

$-\infty \le x\le \infty$

$-\infty \le x+2\le \infty$

$0\le |x+2|\le \infty$

$-1\le |x+2|-1\le \infty$

$-1\le f\left(x\right)\le \infty$

$sominimumvalueis-1andthereisnomaximumvalue.$