CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
104
You visited us 104 times! Enjoying our articles? Unlock Full Access!
Question

Find the maximum force F to be applied for the system shown, so that the two blocks move together. Given that it accelerates with 2 m/s2. Take g=10 m/s2. (μ1=0.2, μ2=0.3)


A
20 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
30 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
40 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
50 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 50 N
We know that , when the block move together the maximum force,
Fmax=(m1+m2)(μ1g+as)
(m1=8 kg; m2=2 kg; μ1=0.3; μ2=0.2)

Hence, F=(10)(0.3×10+2)=50 N

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Warming Up: Playing with Friction
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon