Question

Find the maximum force $F$ to be applied on the system shown, so that the two blocks move together. Take $g=10{\text{m/s}}^2$.

• A. $50\text{N}$
• B. $100\text{N}$
• C. $150\text{N}$
• D. $200\text{N}$

Answer 1

The correct option is C $150\text{N}$

Given,
$m_1=40kg,m_2=10kg,{\mu }_1=0.1,{\mu }_2=0.2$
We know that,
$F_{max}=f_1+(m_1+m_2)a_s$
$(a_s={\mu }_{2}g)$
$F_{max}=(m_1+m_2){\mu }_{1}g+(m_1+m_2)a_s$
$F_{max}=(m_1+m_2)({\mu }_{1}g+{\mu }_{2}g)$
$F_{max}=\left(50\right)\left(0.3\right)10=150\text{N}$
Hence the maximum force which can be applied on the system is $\text{150 N}$