Find the maximum number of students among whom 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and the same number of pencils.

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Solution

The correct option is B 91
Since we are talking about the “maximum” number of students, we need to find the HCF of the given numbers.
$1001 = 7 \times 11 \times 13)$
$910 = 2 \times 5 \times 7 \times 13$
Thus, their HCF is $7 \times 13 = 91.$
Hence, the required number of students is 91.

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