Find the maximum value of 5 + (sinx−4)2
Maximum value of 5 + (sinx−4)2 is 5 + maximum value of (sinx−4)2. So we want to find the maximum value of (sinx−4)2
Sinx varies from -1 to 1.|sinx - 4| is the distance of sinx from 4.This distance is maximum when sinx is -1 (sinx−4)2 will be maximum when |sinx - 4| is maximum.This happens when sinx = -1
⇒ Maximum value = 5 + (−1−4)2
= 5 + 52
= 30