Question

# Find the maximum value of M/m in the situation shown in figure so that the system remains at rest. Friction coefficient at both the contacts is $$\mu$$

A
μsinθμcosθ
B
2μsinθμcosθ
C
μsinθ+μcosθ
D
μcosθμsinθ

Solution

## The correct option is C $$\dfrac{\mu}{sin \theta+\mu \, cos \theta}$$$$\begin{array}{l} \text { Correct option is } C C) \\ \text { If the system is at rest; } \\ \text { Fnet }=0 \end{array}$$ $$\begin{array}{l} \operatorname{Mg} \sin \theta-\text { Friction }=0 \\ \operatorname{Mg} \sin \theta-\mu(\operatorname{Mg} \cos \theta+m g)=0 \end{array}$$ $$\begin{array}{c} M(g \sin \theta-\mu g \cos \theta)=\mu m g \\ M / m=\frac{u}{\sin \theta+\mu \cos \theta} \end{array}$$Physics

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