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Question

Find the maximum value of M/m in the situation shown in figure so that the system remains at rest. Friction coefficient at both the contacts is $$\mu$$
1134384_d352dcf146604bc7b77f33ee88f51839.png


A
μsinθμcosθ
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B
2μsinθμcosθ
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C
μsinθ+μcosθ
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D
μcosθμsinθ
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Solution

The correct option is C $$\dfrac{\mu}{sin \theta+\mu \, cos \theta}$$
$$ \begin{array}{l} \text { Correct option is } C C) \\ \text { If the system is at rest; } \\ \text { Fnet }=0 \end{array} $$

$$ \begin{array}{l} \operatorname{Mg} \sin \theta-\text { Friction }=0 \\ \operatorname{Mg} \sin \theta-\mu(\operatorname{Mg} \cos \theta+m g)=0 \end{array} $$

$$ \begin{array}{c} M(g \sin \theta-\mu g \cos \theta)=\mu m g \\ M / m=\frac{u}{\sin \theta+\mu \cos \theta} \end{array} $$

Physics

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