Find the maximum value of n such that 77 - 42 - 37 - 57 - 30 - 90 - 70 - 2400 - 2402 - 243 - 343 is perfectly divisible by 21 n-A- 9B- 10C- 11D- 6

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Find the maximum value of n such that $77 \times 42 \times 37 \times 57 \times 30 \times 90 \times 70 \times 2400 \times 2402 \times 243 \times 343$ is perfectly divisible by $21^{n}$ .

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Similar questions

570 \times 60 \times 30 \times 90 \times 100 \times 500 \times 700 \times 343 \times 720 \times 81

30^{n}

42 \times 57 \times 92 \times 91 \times 52 \times 62 \times 63 \times 64 \times 65 \times 66 \times 67

42^{n}

720^{n}

10^{n}

12^{n}

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