Find the maximum velocity for skidding for a car moved on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2

0.14 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

140 m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.4 km/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14 m/s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
14 m/s

$V_{m a x} = \sqrt{μ r g} = \sqrt{0.2 \times 100 \times 9.8} = 14 m / s$

Suggest Corrections

Similar questions

Q. A car moves in a circular track of radius 100m. The coefficient of friction between the road and the track is 0.2. Find the maximum velocity the car can move with, without skidding.

Find the maximum velocity for skidding for a car moved on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2

Q. A car has to move on a level turn of radius

45 m

. If the coefficient of static friction between the tyre and the road is

μ_{s} = 2.0

, find the maximum speed the car can take without skidding.

A car has to move on a level turn of radius 90 m. If the coefficient of static friction between the tyre and the road is 1.0, find the maximum speed the car can take without skidding.

Q. A car moves on a horizontal track of radius

r

, the speed increasing constantly at rate

\frac{d v}{d t}

= a

. The coefficient of friction between road and tyre is

μ

. Find the speed at which the car will skid.

Join BYJU'S Learning Program

Find the maximum velocity for skidding for a car moved on a circular track of radius 100 m. The coefficient of friction between the road and tyre is 0.2

The correct option is D 14 m/s Vmax=√μrg=√0.2×100×9.8=14m/s

The correct option is D
14 m/s

$V_{m a x} = \sqrt{μ r g} = \sqrt{0.2 \times 100 \times 9.8} = 14 m / s$