Find the mean age in years from the frequency distribution given below:
Class interval of age in yearsFrequency(fi)25−29430−351435−392240−451645−49650−55555−593Total70
39.35
Class mark for first class interval =
Upper class limit + Lower class limit2=25+292=27
Similarly the class mark for each class interval can be found.
Class intervalFrequency(fi)Class mark(xi)fixi25−2942710830−35143244835−39223781440−45164267245−4964728250−5555226055−59357171Total∑fi=70∑fixi=2755Mean=∑fixi∑fi=275570=39.4