Find the mean age in years from the frequency distribution given below: ClassintervalofFrequencyageinyears(fi)25−29430−351435−392240−451645−49650−55555−593Total70
A
39.35
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B
39.39
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C
40.15
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D
40.39
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Solution
The correct option is A 39.35 Classfixifixiinterval25−2942710830−35143244835−39223781440−45164267245−4964728250−5555226055−59357171Total∑fi=702755Mean=∑fixi∑fi=275570=39.4