Question

Find the mean and median of all the positive factors pf 24

Answer 1

$$\begin{gathered} \mathrm{The}\mathrm{factors}\mathrm{of}24\mathrm{are}: \\ 1,2,3,4,6,8,12\mathrm{and}24 \\ \mathrm{Mean}=\frac{\mathrm{sum}\mathrm{of}\mathrm{observations}}{\mathrm{number}\mathrm{of}\mathrm{observations}}=\frac{1+2+3+4+6+8+12+24}{8}=\frac{60}{8}=7.5 \\ \mathrm{number}\mathrm{of}\mathrm{observations},\mathrm{n}=8\left(\mathrm{even}\right) \\ \mathrm{median}=\frac{\mathrm{value}\mathrm{of}{\left({\displaystyle \frac{\mathrm{n}}{2}}\right)}^{\mathrm{th}}\mathrm{observation}+\mathrm{value}\mathrm{of}{\left({\displaystyle \frac{\mathrm{n}}{2}}+1\right)}^{\mathrm{th}}\mathrm{observation}}{2} \\ =\frac{\mathrm{value}\mathrm{of}{\left({\displaystyle \frac{8}{2}}\right)}^{\mathrm{th}}\mathrm{obs}.+\mathrm{value}\mathrm{of}{\left({\displaystyle \frac{8}{2}}+1\right)}^{\mathrm{th}}\mathrm{obs}.}{2} \\ =\frac{\mathrm{value}\mathrm{of}{4}^{\mathrm{th}}\mathrm{obs}.+\mathrm{value}\mathrm{of}{5}^{\mathrm{th}}\mathrm{obs}.}{2} \\ =\frac{4+6}{2} \\ =5 \end{gathered}$$