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Question

Find the mean , and standard deviation for the following data :

(i) Year render:102030405060No of person (cumulative):1532517897109

(ii) Marks:2345678910111213141516Frequency:166882230210001

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Solution

xiCumFreqfifixifix2i101515150150020321734068003051195701710040782710804320050971995047500601091272043200N=109Total=3810Total=159300

Mean ¯¯¯¯¯X=3810109=34.95

Var =159300109(34.95)2=239.96

SD = 239.96=15.49

xififixifix2i2124361854462496584020068482887214988216128932724310000112222421211214413000140001500016116256N=40Total=239Total=1753

Mean =23940=5.975

Var =175340(5.975)2=8.12

SD = 8.12=2.85


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