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Question

Find the mean and variance for the following frequency distribution.

Class 030 3060 6090 90120 120150 150180 180210 Frequencies 2 3 5 10 3 5 2

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Solution

Mid valuesClasses xi fiu=x10530fufu2030 15 2 36183060 45 3 26126090 75 5 15 590120 105 10 0 0 0120150 135 3 1 3 3150180 165 5 21020180210 195 2 3 61830 276

Mean (¯¯¯x)=A+fuN×h=105+230×30=107

Variance (σ2)=h2N2[Nfu2(fu)2]


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