CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the mean and variance for the following frequency distribution.

Class 010 1020 2030 3040 4050 Frequencies 5 8 15 16 6

Open in App
Solution

Mid valuesClasses xi fiu=x10530fufu2010 5 5 26181020 15 8 16122030 25 15 05 53040 35 16 1 0 04050 45 6 2 3 350 1068

Mean(¯¯¯x)=A+fuN×h=25+1050×10=25+2=27

Variance(σ2)=h2N2[Nfu2(fu)2] =(10)2(50)2[50×68(10)2]=1002500[3400100]=125×3300=132.


flag
Suggest Corrections
thumbs-up
58
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mean Deviation for Grouped Data
STATISTICS
Watch in App
Join BYJU'S Learning Program
CrossIcon