Find the mean- array - c - c - Wline Observation - 3 - 6 - 789 - 10 Nlhline frequency - 8 - 10 - 15 - 9 - 8 Nlhlinelend array A- 7B- 6C- 5D- 8

The correct option is A 7 The total sumnbsp; =8 times;3 + 6 times;10 + 7 times;15 + 9 times;9 + 10 times;8 = 350 Total frequency = 50 Mean= nbsp;su ...

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Byju's Answer

Standard IX

Mathematics

Mean

Find the mean...

Question

Find the mean.

$\begin{matrix} O b s e r v a t i o n & 3 & 6 & 7 & 9 & 10 f r e q u e n c y & 8 & 10 & 15 & 9 & 8 \end{matrix}$

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Solution

The correct option is A
7

The total sum $= 8 \times 3 + 6 \times 10 + 7 \times 15 + 9 \times 9 + 10 \times 8 = 350$

Total frequency = 50

$M e a n = \frac{s u m o f a l l f r e q u e n c i e s}{t o t a l f r e q u e n c y}$

$M e a n = \frac{350}{7} = 7$

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Similar questions

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Find the mean. Observation367910frequency8101598

The correct option is A 7 The total sum=8×3+6×10+7×15+9×9+10×8=350 Total frequency = 50 Mean=sum of all frequenciestotal frequency Mean=3507=7

Find the mean.

$\begin{matrix} O b s e r v a t i o n & 3 & 6 & 7 & 9 & 10 f r e q u e n c y & 8 & 10 & 15 & 9 & 8 \end{matrix}$

The correct option is A
7

The total sum $= 8 \times 3 + 6 \times 10 + 7 \times 15 + 9 \times 9 + 10 \times 8 = 350$

Total frequency = 50

$M e a n = \frac{s u m o f a l l f r e q u e n c i e s}{t o t a l f r e q u e n c y}$

$M e a n = \frac{350}{7} = 7$