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Question

Find the mean deviation about mean for the following data.
15,18,13,16,12,24,10,20

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Solution

Mean Deviation =|¯¯¯xx1|+|¯¯¯xx2|+...+|¯¯¯xxn|n
where, ¯¯¯x=x1+x2+x2...+xnn
on substituting values
¯¯¯x=15+18+13+16+12+24+10+208=1288=16
Mean Deviation =|1615+|1816|+|1316|+|1616|+|1612|+|1624|+|1610|+|1620|
=1+2+3+0+4+8+6+48=288=3.5

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