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Question

Find the mean deviation about the following continuous distribution:
Class interval0101020203030404050506060707080
Frequency5871228201010

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Solution

Class interval 010 1020 2030 3040 4050 5060 6070 7080
Frequency 5 8 7 12 28 20 10 10

Mean deviation about mean

Class interval frequency(fi) Mid value(xi) fixi
010 5 5 25
1020 8 15 120
2030 7 25 175
3040 12 35 420
4050 28 45 1260
5060 20 55 1210
6070 10 65 650
7080 10 75 750

fi=100

fixi=4610

Mean (¯x)=fixifi

=4610100

=46.1

Class interval frequency(fi) mid value(xi) |xi¯x| fi|xi¯x|
010 5 5 |546.1|=41.1 205.5
1020 8 15 |1546.1|=31.1 248.8
2030 7 25 |2546.1|=21.1 147.7
3040 12 35 |3546.1|=11.1 133.2
4050 28 45 |4546.1|=1.1 30.8
5060 20 55 |5546.1|=8.9 178
6070 10 65 |6546.1|=18.9 189
7080 10 75 |75046.1|=28.9 289
Total 100 _____
1422
Mean deviation about mean M.D(¯x)=fi|xi¯x|fi
=1422100

=14.22.

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