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Question

Find the mean deviation about the mean for the following data.
Class interval010102020303040405050606070Frequency812108327

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Solution

Assumed mean A = 35
ClassMidvalue xFrequency fdi=x3510fidi|xi¯x|fi|xi¯x|010583242419210201512224141682030251011044030403580064840504531316485060552242652607065732136252fi=50fidi=(30)800
¯x=A+fidifi×h
A=35
h=10
¯x=35+3050×10
=356=29
M.D.(¯x)=fi|xi¯x|fi
=80050=16.

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