Question

Find the mean deviation about the mean for the given data.

Q2. 38, 70, 48, 40, 42, 55, 63, 46, 54, 44

Answer 1

Mean of the given data is

$\overline{x}=\frac{38+70+48+40+42+55+63+46+54+44}{10}=\frac{500}{10}$ = 50

$\begin{array}{cc}{x}_1& |x_i-\overline{x}|\\ 38& 12\\ 70& 20\\ 48& 2\\ 40& 10\\ 42& 8\\ 55& 5\\ 63& 13\\ 46& 4\\ 54& 4\\ 44& 6\\ \text{Total}& 84\end{array}$

$\text{M.D. about mean}=\frac{1}{n}{\sum }_{i-1}^n|x_i-\overline{x}|=\frac{1}{10}\times 84=8.4$