Find the mean marks per student, using assumed-mean method:
Marks0−1010−2020−3030−4040−5050−60Number of students12182720176
Class | Frequency (fi) | Mid values (xi) | Deviation (di) di = (xi – 25) | (fidi) |
0 – 10 | 12 | 5 | -20 | -240 |
10 – 20 | 18 | 15 | -10 | -180 |
20 – 30 | 27 | 25 = A | 0 | 0 |
30 – 40 | 20 | 35 | 10 | 200 |
40 – 50 | 17 | 45 | 20 | 340 |
50 – 60 | 6 | 55 | 30 | 180 |
Total | ∑fi=100 | ∑(fi×di)=300 |
Let A = 25 be the assumed mean.
Then we have
Mean=A+∑fidi∑fi=25+300100=28