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Question

Find the mean, median and mode of the following frequency distribution:
1373795_ebe3e87dac71468cbc353d4fcc852fa9.png

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Solution

Given
Class 010 1020 2030 3040 4050
Frequency 5 27 58 20 10
(i) Mean
Class Mid point(xi) Frequency(fi) fixi
010 5 5 25
1020 15 27 405
2030 25 58 1450
3040 35 20 700
4050 45 10 450
Here
fi=120
fixi=3030
Mean (¯x)=fixifi=3030120
25.25
(ii) Median
Class Frequency Cumulative frequency
010 5 5
1020 21 32(cf)
2030(l) 58(f) 90
3040 20 110
4050 10 120
(iii) Mode
Class Frequency
010 5
1020 27 fo
2030(l) 58f1
3040 20f2
4050 10
N=120N2=60
so median class is 2030
l=20, class width=h=10
Median =l+⎜ ⎜ ⎜N2cff⎟ ⎟ ⎟×h
=20+603258×10
=20+2858×10=20+28058
=20+4.83
=24.83
Mean=25.25
So model class is 2030
Mode=l+(f1fo2f1fof2)×h
=20+58272×582720×10
=20+31069
=20+4.493
=24.493

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