Find the mean of:
$6.2, 5.6, 4.8, 11.2, 12.5, 7.4$ and $6.3$

7 \frac{5}{7}

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8 \frac{5}{7}

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9 \frac{5}{7}

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10 \frac{5}{7}

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Solution

The correct option is D $7 \frac{5}{7}$
We need to find mean of $6.2, 5.6, 4.8, 11.2, 12.5, 7.4$ and $6.3$ .
Therefore, mean $= \frac{6.2 + 5.6 + 4.8 + 11.2 + 12.5 + 7.4 + 6.3}{7}$
$= \frac{54}{7}$
$= 7 + \frac{5}{7}$
$= 7 \frac{5}{7}$

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Similar questions

Find the mean, variance and standard deviation using short-cut method

$\begin{matrix} Height in cm & 70 - 75 & 75 - 80 & 80 - 85 & 85 - 90 & 90 - 95 & 95 - 100 & 100 - 105 & 105 - 110 & 110 - 115 No. of children & 3 & 4 & 7 & 7 & 15 & 9 & 6 & 6 & 3 \end{matrix}$

Compute the mode from the following data:
$\begin{matrix} Size & 45 - 55 & 55 - 65 & 65 - 75 & 75 - 85 & 85 - 95 & 95 - 105 & 105 - 115 Frequency & 7 & 12 & 17 & 30 & 32 & 6 & 10 \end{matrix}$

Find the mean, variance and standard deviation using short-cut method

Height in cms	No. of children
70-75	3
75-80	4
80-85	7
85-90	7
90-95	15
95-100	9
100-105	6
105-110	6
110-115	3

In the given figure two parallel lines l,m are intersected by a tranversal. If $∠ 1 = 105^{\circ}$ then $∠ 7$ and $∠ 8$ are

Q. Compute the mode from the following series:

Size	45-55	55-65	65-75	75-85	85-95	95-105	105-115
Frequency	7	12	17	30	32	6	10

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Find the mean of:6.2,5.6,4.8,11.2,12.5,7.4 and 6.3

The correct option is D 757We need to find mean of 6.2,5.6,4.8,11.2,12.5,7.4 and 6.3.Therefore, mean =6.2+5.6+4.8+11.2+12.5+7.4+6.37=547=7+57=757

Find the mean of:
$6.2, 5.6, 4.8, 11.2, 12.5, 7.4$ and $6.3$

The correct option is D $7 \frac{5}{7}$
We need to find mean of $6.2, 5.6, 4.8, 11.2, 12.5, 7.4$ and $6.3$ .
Therefore, mean $= \frac{6.2 + 5.6 + 4.8 + 11.2 + 12.5 + 7.4 + 6.3}{7}$
$= \frac{54}{7}$
$= 7 + \frac{5}{7}$
$= 7 \frac{5}{7}$