Find the mean of each of the following frequency distributions:
Class interval: 0-6 6-12 12-18 18-24 24-30
Frequency: $6$ $8$ $10$ $9$ $7$

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Solution

Answer:-
Class interval Frequency $x_{i}$ $f_{i} x_{i}$
0-6 6 3 18
6-12 8 9 72
12-18 10 15 150
18-24 9 21 189
24-30 7 27 189
$Σ f_{i} = 40$ $Σ f_{i} x_{i} = 618$
$m e a n = \frac{Σ f_{i} x_{i}}{Σ f_{i}} = \frac{618}{40} = 15.45$

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Q. Calculate mean deviation from the median of the following data:

Class interval:	0-6	6-12	12-18	18-24	24-30
Frequency:	4	5	3	6	2

The median of the distribution given below is 14.4. Find the values of x and y, if the total frequency is 20.
Class interval: 0-6 6-12 12-18 18-24 24-30
Frequency: 4 x 5 y 1

Q. Find the mean of each of the following frequency distributions :

Class interval:	0−8	8−16	16−24	24−32	32−40
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Q. Prepare a less than ogive from the following data:

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Q. Consider the following frequency distribution:

\begin{matrix} Class: & 0 - 6 & 6 - 12 & 12 - 18 & 18 - 24 & 24 - 30 Frequency : & a & b & 12 & 9 & 5 \end{matrix}

If mean

= \frac{309}{22}

and median

= 14,

then the value

(a - b)^{2}

is equal to

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Class interval	Frequency	$x_{i}$	$f_{i} x_{i}$
0-6	6	3	18
6-12	8	9	72
12-18	10	15	150
18-24	9	21	189
24-30	7	27	189
	$Σ f_{i} = 40$		$Σ f_{i} x_{i} = 618$

Find the mean of each of the following frequency distributions:Class interval:0-66-1212-1818-2424-30Frequency:681097

Answer:-Class interval Frequency xi fixi 0-6 6 3 18 6-12 8 9 72 12-18 10 15 150 18-24 9 21 189 24-30 7 27 189 Σfi=40 Σfixi=618 mean=ΣfixiΣfi=61840=15.45

Find the mean of each of the following frequency distributions:
Class interval: 0-6 6-12 12-18 18-24 24-30
Frequency: $6$ $8$ $10$ $9$ $7$

Answer:-
Class interval Frequency $x_{i}$ $f_{i} x_{i}$
0-6 6 3 18
6-12 8 9 72
12-18 10 15 150
18-24 9 21 189
24-30 7 27 189
$Σ f_{i} = 40$ $Σ f_{i} x_{i} = 618$
$m e a n = \frac{Σ f_{i} x_{i}}{Σ f_{i}} = \frac{618}{40} = 15.45$