Find the mean of the first $10$ natural numbers.

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Solution

Given data 1, 2, 3, .......10
$∴$ Arithmetic mean (A. M)
$= \frac{T h e s u m o f o b s e r v a t i o n s}{T h e t o t a l n u m b e r o f o b s e r v a t i o n s}$
$= \frac{1 + 2 + 3 + . . . + 10}{10} = \frac{55}{10} = 5.5$

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