Find the mean of the following data, using assumed-mean method:
Marks100−120120−140140−160160−180180−200Number of students102030155
Class | Frequency (fi) | Mid values (xi) | Deviation (di) di = (xi - 150) | (fidi) |
100 - 120 | 10 | 110 | -40 | -400 |
120 - 140 | 20 | 130 | -20 | -400 |
140 - 160 | 30 | 150 = A | 0 | 0 |
160 - 180 | 15 | 170 | 20 | 300 |
180 - 200 | 5 | 190 | 40 | 200 |
Total | ∑fi=80 | ∑(fi×di)=−300 |
Let A = 150 be the assumed mean. Then we have:
Mean, ¯x=A+[∑(fi×di)/∑fi]
= 150 + (-300/80)
= 150 - 3.75
Therefore, ¯x= 146.25