Find the mean of the following data- using Step Deviation method method- - Marks 110 130 150 170 190- Number of students 10 20 30 15 5- -

Marks Frequency (fi) nbsp; Deviation (di) nbsp; di nbsp;= (xi nbsp;150) (fidi) 110 10 nbsp; 40 ...

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Standard X

Mathematics

Coefficient of Variation

Find the mean...

Question

Find the mean of the following data, using Step Deviation method method:
$\begin{matrix} Marks & 110 & 130 & 150 & 170 & 190 Number of students & 10 & 20 & 30 & 15 & 5 \end{matrix}$

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Solution

Marks Frequency (fi) Deviation (di)
di = (xi - 150)
(fidi)

110 10 -40 -400

130 20 -20 -400

150 = A 30 0 0

170 15 20 300

190 5 40 200

Total ∑fi=80 ∑(fi×di)=−300

Let A = 150 be the assumed mean. Then we have:

Mean, $¯ x$ =A+[∑(fi×di)/∑fi]

= 150 + (-300/80)

= 150 - 3.75

Therefore, $¯ x$ = 146.25

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Marks	Frequency (fi)	Deviation (di) di = (xi - 150)	(fidi)
110	10	-40	-400
130	20	-20	-400
150 = A	30	0	0
170	15	20	300
190	5	40	200
Total	∑fi=80		∑(fi×di)=−300

Find the mean of the following data, using Step Deviation method method: Marks110130150170190Number of students102030155

Marks Frequency (fi) Deviation (di) di = (xi - 150) (fidi) 110 10 -40 -400 130 20 -20 -400 150 = A 30 0 0 170 15 20 300 190 5 40 200 Total ∑fi=80 ∑(fi×di)=−300 Let A = 150 be the assumed mean. Then we have: Mean, ¯x=A+[∑(fi×di)/∑fi] = 150 + (-300/80) = 150 - 3.75 Therefore, ¯x= 146.25

Find the mean of the following data, using Step Deviation method method:
$\begin{matrix} Marks & 110 & 130 & 150 & 170 & 190 Number of students & 10 & 20 & 30 & 15 & 5 \end{matrix}$