Find the mean of the following data without Outlier.
Data : 35, 45, 5, 25, 55.

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Solution

The correct option is C 40
Arranging the data in ascending order: 5, 25, 35, 45, 55
'5' is the value that is very small as compared to the other values.
'5' is the Outlier.

Mean with Outlier $= \frac{5 + 25 + 35 + 45 + 55}{5} = 33$
Mean without Outlier $= \frac{25 + 35 + 45 + 55}{4} = 40$

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Find the mean of the following data without Outlier. Data : 35, 45, 5, 25, 55.

The correct option is C 40Arranging the data in ascending order: 5, 25, 35, 45, 55 '5' is the value that is very small as compared to the other values. '5' is the Outlier. Mean with Outlier =5+25+35+45+555=33 Mean without Outlier =25+35+45+554=40

Find the mean of the following data without Outlier.
Data : 35, 45, 5, 25, 55.

The correct option is C 40
Arranging the data in ascending order: 5, 25, 35, 45, 55
'5' is the value that is very small as compared to the other values.
'5' is the Outlier.

Mean with Outlier $= \frac{5 + 25 + 35 + 45 + 55}{5} = 33$
Mean without Outlier $= \frac{25 + 35 + 45 + 55}{4} = 40$