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B
200
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C
100
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D
249.2
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Solution
The correct option is A 149.2 Class MarkFrequencyfx1101011001301316901508120017071190190122280 N=50 ∑fx = 7460 Note that ¯¯¯x = ∑fxN, where ¯¯¯x stands for mean and N stands for the sum of frequencies. ⟹Mean=746050=149.2