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Question

Find the mean of the following distribution.

Class100120120140140160160180180200Frequency10138712

A
149.2
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B
200
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C
100
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D
249.2
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Solution

The correct option is A 149.2
Class MarkFrequencyfx1101011001301316901508120017071190190122280
N=50
fx = 7460
Note that ¯¯¯x = fxN,
where ¯¯¯x stands for mean and N stands for the sum of frequencies.
Mean=746050=149.2

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