Find the mean of the following distribution-Class - 100-120 - 120-140 - 140-160 - 160-180 - 180-200 WhlineFrequency - 10 - 13 - 8 - 7 - 12 Whline -endarray

[ Class Mark amp; Frequency amp; f_ix_i; 110 amp; 10 amp; 1100; 130 amp; 13 amp; 1690; 150 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Finding Mean for Grouped Data When Class Intervals Are Not Given

Find the mean...

Question

Find the mean of the following distribution.

$\begin{matrix} C l a s s & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 F r e q u e n c y & 10 & 13 & 8 & 7 & 12 \end{matrix}$

Open in App

Solution

$\begin{matrix} Class Mark & Frequency & f_{i} x_{i} 110 & 10 & 1100 130 & 13 & 1690 150 & 8 & 1200 170 & 7 & 1190 190 & 12 & 2280 \end{matrix}$
$\sum f_{i}$ =50
$\sum f_{i} x_{i}$ = 7460
Mean = $\frac{7460}{50} = 149.2$

Suggest Corrections

Similar questions

Q. Find the mean daily wages

Daily wages	No. of workers
$100 - 120$	$12$
$120 - 140$	$14$
$140 - 160$	$8$
$160 - 180$	$6$
$180 - 200$	$10$

Use appropriate method.

Find the mode of the following data.
$\begin{matrix} C l a s s i n t e r v a l & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 F r e q u e n c y & 10 & 13 & 8 & 7 & 12 \end{matrix}$

Find the mean of the following data, using assumed-mean method:
$\begin{matrix} Marks & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 Number of students & 10 & 20 & 30 & 15 & 5 \end{matrix}$

Find the mean, using assumed-mean method:

$\begin{matrix} Class & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 Frequency & 10 & 20 & 30 & 15 & 5 \end{matrix}$

Q. The following table gives the daily income of

50

workers of a factory:

Daily income (in Rs.)	$100 - 120$	$120 - 140$	$140 - 160$	$160 - 180$	$180 - 200$
Number of workers:	$12$	$14$	$8$	$6$	$10$

Find the mean, mode and median of the above data

Join BYJU'S Learning Program

Find the mean of the following distribution. Class100−120120−140140−160160−180180−200Frequency10138712

Class MarkFrequencyfixi1101011001301316901508120017071190190122280 ∑fi=50 ∑fixi = 7460 Mean = 746050=149.2

Find the mean of the following distribution.

$\begin{matrix} C l a s s & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 F r e q u e n c y & 10 & 13 & 8 & 7 & 12 \end{matrix}$

$\begin{matrix} Class Mark & Frequency & f_{i} x_{i} 110 & 10 & 1100 130 & 13 & 1690 150 & 8 & 1200 170 & 7 & 1190 190 & 12 & 2280 \end{matrix}$
$\sum f_{i}$ =50
$\sum f_{i} x_{i}$ = 7460
Mean = $\frac{7460}{50} = 149.2$