1
Question
Find the mean of the following distribution by step deviation method: [4 MARKS]
Class intervalFrequency20−301030−40640−50850−601260−70570−809
Class intervalFrequency20−301030−40640−50850−601260−70570−809
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Solution
Formula: 2 Marks
Solution: 2 Marks
We take as A = 45
C.I.fxu=x−Ahfu20−301025−2−2030−40635−1−640−508450050−60125511260−7056521070−80975327∑f=50∑fu=23
Mean =A+∑fu∑f×h=45+2350×10
= 45 - 4.6 = 49.6
Solution: 2 Marks
We take as A = 45
C.I.fxu=x−Ahfu20−301025−2−2030−40635−1−640−508450050−60125511260−7056521070−80975327∑f=50∑fu=23
Mean =A+∑fu∑f×h=45+2350×10
= 45 - 4.6 = 49.6
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