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Question

Find the mean of the following frequency distribution using a suitable method:
Class20303040405050606070Frequency2540423310

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Solution

Let us choose a = 45, h = 10,
then di = xi - 45
and ui = (xi−45)/10

Using Step-deviation method, the given data is shown as follows:

Class Frequency (fi) Class mark (xi) di= xi- 45 ui = (xi−45)/10 fiui
20 - 30 25 25 -20 -2 -50
30 - 40 40 35 -10 -1 -40
40 - 50 42 45 0 0 0
50 - 60 33 55 10 1 33
60 - 70 10 65 20 2 20
Total ∑fi=150 ∑(fi×ui)=−37

The mean of given data is given by

¯x=a+(∑fiui/∑fi)×h

= 45 + (-37/150) x 10

= 45 - 37/15

= 45 - 2.466

= 42.534

Thus, the mean is 42.534.


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