Find the mean of the following frequency distribution using a suitable method:
Class20−3030−4040−5050−6060−70Frequency2540423310
Let us choose a = 45, h = 10,
then di = xi - 45
and ui = (xi−45)/10
Using Step-deviation method, the given data is shown as follows:
Class | Frequency (fi) | Class mark (xi) | di= xi- 45 | ui = (xi−45)/10 | fiui |
20 - 30 | 25 | 25 | -20 | -2 | -50 |
30 - 40 | 40 | 35 | -10 | -1 | -40 |
40 - 50 | 42 | 45 | 0 | 0 | 0 |
50 - 60 | 33 | 55 | 10 | 1 | 33 |
60 - 70 | 10 | 65 | 20 | 2 | 20 |
Total | ∑fi=150 | ∑(fi×ui)=−37 |
The mean of given data is given by
¯x=a+(∑fiui/∑fi)×h
= 45 + (-37/150) x 10
= 45 - 37/15
= 45 - 2.466
= 42.534
Thus, the mean is 42.534.