Find the mean of the following frequency distribution using step-deviation method.
Class0−1010−2020−3030−4040−50Frequency71015810
Let us choose a = 25, h = 10,
then di = xi - 25
and
ui = (xi−25)/10
Using Step-deviation method, the given data is shown as follows:
Class | Frequency (fi) | Class mark (xi) | di= xi- 25 | ui = (xi−25)/10 | fiui |
0 - 10 | 7 | 5 | -20 | -2 | -14 |
10 - 20 | 10 | 15 | -10 | -1 | -10 |
20 - 30 | 15 | 25 | 0 | 0 | 0 |
30 - 40 | 8 | 35 | 10 | 1 | 8 |
40 - 50 | 10 | 45 | 20 | 2 | 20 |
Total | ∑fi=50 | ∑(fi×ui)=4 |
The mean of given data is given by
¯x=a+(∑fiui/∑fi)×h
= 25 + 4/50 x 10
= 25 + 4/5
= (125+4)/5
= 129/5
= 25.8
Thus, the mean is 25.8.