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Question

Find the mean of the following frequency distribution using step-deviation method.
Marks obtainednumber of students
Less than 1014
Less than 2022
Less than 3037
Less than 4055
Less than 5067
Less than 6075

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Solution

Step deviation method
class interval number of students (f) mid point of class interval Deviation
di=xiAh
fidi
0-10
10-20
20-30
30-40
40-50
50-60
14
22
37
55
67
75
5
15
25
35
45
55
-2
-1
0
1
2
3
-28
-22
0
55
134
225
total f=270 fidi=364

By step deviation method

mean =A+fidif×h

=25+364270×10

=25+36427

=25+13.48

mean =38.48

where h is class width
h=10

A is assumed mean
A=25

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