Find the mean weight from the following table.
Weight $(k g)$ $29$ $30$ $31$
$32$ $33$
No.of children $20$ $01$ $04$ $03$ $05$

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Solution

Weight $(k g)$
$(x_{i})$ No. of children
$(f_{i})$ $f_{i} x_{i}$
$29$ $20$ $580$
$30$ $1$ $30$
$31$ $4$ $124$
$32$ $3$ $96$
$33$ $5$ $165$
$\sum f_{i} = 33$ $\sum f_{i} x_{i} = 995$
Therefore,
Mean weight $(¯ x) = \frac{\sum f_{i} x_{i}}{\sum f_{i}}$
$\Rightarrow ¯ x = \frac{995}{33} = 30.15 k g$

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Weight $(k g)$	$29$	$30$	$31$	$32$	$33$
No.of children	$20$	$01$	$04$	$03$	$05$