Find the Measure of an angle which is supplement of itself is :

45^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

180^o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90^o

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
90^o

Let the angle be X⁰.

Supplement of this angle is also X.

The sum of the measures of supplementary angle pair is 180⁰.

⇒ X + X = 180⁰

⇒ 2X = 180⁰

⇒ X = 90⁰

Suggest Corrections

Similar questions

90^{o}

180^{o}

{sin}^{2} 30^{o} {cos}^{2} 45^{o} + 4 {tan}^{2} 30^{o} + \frac{1}{2} {sin}^{2} 90^{o} - 2 {cos}^{2} 90^{o}

30^{o}

\frac{x {cosec}^{2} 30^{o} {sec}^{2} 45^{o}}{8 {cos}^{2} 45^{o} {sin}^{2} 90^{o}} = {tan}^{2} 60^{o} - {tan}^{2} 45^{o}

x

Join BYJU'S Learning Program