Given, in triangles,
△PQR and
△XYZ,
side RP = side ZX = 6 cm
∠QRP =
∠YZX = 140°
side QR = side YZ = 9 cm
∴ by SAS criterion for congruency of triangles,
△PQR
≅△XYZ
So,
∠RQP =
∠ZXY = 25° (corresponding parts)
In triangle,
△PQR,
∠PQR = 180° - (
∠RQP +
∠QRP)
⇒ ∠PQR = 180° - (25° + 140°)
⇒ ∠PQR = 15°