The correct option is D 109∘
Given a circle with center at P.Let AB and CD be the chords of the circle which are produced to meet at E. AC and BD intersect at O
Now, ∠BAC=18, ∠AEC=35
In triangleCAE
Sum of angles =180
∠CAE+∠ACE+∠AEC=180
18+35+∠ACE=180
∠ACE=127∘
∠ACD=180−∠ACE=180−127=53∘ (Linear pair)
∠CDB=∠CAB=18∘ (Angles in same segment)
Now, In △ODC
Sum of angles =180
∠ODC+∠OCD+∠COD=180
18+53+y=180
y=109∘