Find the measure of AP- if CD -24 cmA- 12 cmB- 6 cmC- 8 cmD- 10cm

You visited us 1 times! Enjoying our articles? Unlock Full Access!

A Line through the Center That Bisects the Chord Is Perpendicular to the Chord

Find the meas...

Question

Find the measure of AP, if CD = 24cm

12cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 12cm
As the distance from the center to AB and CD are equal, AB and CD are of equal length.
Thus AB = CD = 24 cm.
Perpendicular from the center to a chord bisects the chord.
$⟹$ OP bisects AB.
$⟹$ AP= $\frac{A B}{2}$ = 12 cm

Suggest Corrections

Similar questions

Q. P is the mid-point of side BC of a parallelogram ABCD such that ∠BAP = ∠DAP. If AD = 10 cm, then CD =

(a) 5 cm

(b) 6 cm

(c) 8 cm

(d) 10 cm

In a circle of radius 10 cm given below, chord AB and CD are equal. If OE bisects AB and OF bisects CD and OF = 6 cm, then length EB is ________ .

△

ABC is constructed such that AB = 6 cm, BC = 10 cm and

∠

A = 90

^{\circ}

. Then the length of side AC is

In the given figure, PA and PB are tangents drawn from an external point P to a circle. CD is the third tangent touching the circle at Q. If PB=10cm and CQ=2cm, then the length of PC is:

In the given figure, chords AB and CD when extended meet at P. If AB = 4 cm, BP = 6 cm, DP = 5 cm, then CD =__.

Join BYJU'S Learning Program

Find the measure of AP, if CD = 24cm

The correct option is A 12cmAs the distance from the center to AB and CD are equal, AB and CD are of equal length. Thus AB = CD = 24 cm. Perpendicular from the center to a chord bisects the chord. ⟹ OP bisects AB. ⟹ AP= AB2 = 12 cm

The correct option is A 12cm
As the distance from the center to AB and CD are equal, AB and CD are of equal length.
Thus AB = CD = 24 cm.
Perpendicular from the center to a chord bisects the chord.
$⟹$ OP bisects AB.
$⟹$ AP= $\frac{A B}{2}$ = 12 cm