Find the measure of central angle of Afternoon and night from the following information.
Part of a day Morning Afternoon Evening Night
Percentage of electricity used $20$ $25$ $15$ $10$

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Solution

$c e n t r a l a n g l e o f a f t e r n o o n$
$= \frac{% a g e o f e l e c t r i c i t y u s e d d u r i n g a f t e r n o o n}{t o t a l % a g e} \times 360 = \frac{25}{100} \times 360 = 90^{\circ} A n s .$
$s i m i l a r l y,$
$c e n t r a l a n g l e o f n i g h t$
$= \frac{10}{100} \times 360 = 36^{\circ} A n s .$

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Part of a day	Morning	Afternoon	Evening	Night
Percentage of electricity used	30	40	20	10

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Part of the day	Morning	Afternoon	Evening	Night
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Class interval	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$
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(y + 25^{\circ}), 2 y, (2 y - 15^{\circ})

(y + 20^{\circ})

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