Question

Find the measures of each exterior angle of a regular Heptagon

Answer 1

In a regular heptagon, all sides are same size and measure of all interior angles are same.
The sum of interior angles of heptagon is
$(n-2)\times {180}^o$ where $n$ is number of sides of polygon.
$(7-2)\times {180}^o={900}^o$ here $n=7$ because hepta means $7$
Each interior angle $=900/7={128.57}^o$
As we know that the sum of interior and exterior angles is ${180}^o$
Exterior angle + interior angle $={180}^o$
Exterior angle $+{128.57}^o={180}^o$
Exterior angle $={180}^o-{128.57}^o={51.43}^o$