Question

Find the measures of each exterior angle of a regular Hexagon

Answer 1

In a regular hexagon, all sides are same size and measure of all interior angles are same.

The sum of interior angles of a regular polygon is given by $(n-2)\times {180}^o$ where $n$ is number of sides of polygon.

Sum of interior anles $=(6-2)\times {180}^o={720}^o$ here $n=6$ (because hexa means $6$)

Each interior angle $=720/6={120}^o$
As we know that the sum of interior and exterior angles is ${180}^o$
Exterior angle + interior angle $={180}^o$
Exterior angle $+{120}^o={180}^o$
Exterior angle $={180}^o-{120}^o={60}^o$