Question

Find the measures of each interior angles of a regular polygon having $10$ sides

Answer 1

In a regular having $10$ sides, all sides are of same size and measure of all interior agles is the same.

The sum of interior angles of polygon is $(n-2)\times {180}^o$ where $n$ is the number of sides of polygon

$(10-2)\times {180}^o={1440}^o$ here $n=10$

Each interior angle $=1440/10={144}^o$