Find the median class for the following data given below $:$
Number of cars
$0 - 10$
$10 - 20$
$20 - 30$
$30 - 40$
$40 - 50$
$50 - 60$
$60 - 70$
$70 - 80$
Frequency
$7$
$9$
$13$
$21$
$12$
$15$
$4$
$12$

30 - 40

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40 - 50

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50 - 60

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60 - 70

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Solution

The correct option is A $30 - 40$
To find the median class $:$
First add the total number of frequencies.
Here, $f = 93$
$= \frac{(T o t a l n u m b e r o f f r e q u e n c y)}{2}$
$= (93) / 2 = 46.5$
Hence, the value 46.5 lies in the class interval 30-40 from the cummulative frequency table.

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Similar questions

Q. Find the Mean Deviation about median for the following data :

Class	0 - 10	10 - 20	20 - 30	30 - 40	40 - 50	50 - 60	60 - 70	70 - 80
frequency	5	8	7	12	28	20	10	10

Q. The marks obtained by 40 students of a class are given below :

80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70, 10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80, 90,

50, 80, 60, 70, 40, 50, 60, 90, 60, 40, 40, 60

, and

60

Construct a frequency distribution table.

Q. The marks obtained by 40 students of a class are given below :

80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70, 10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80,

90, 50, 80, 60, 70, 40, 50, 60, 90, 60, 40, 40, 60

, and

60

How many students obtained marks below

40

The marks obtained by $40$ students of a class are given below :
$80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70,$
$10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80, 90,$ $50, 80,$
$60, 70, 40, 50, 60, 90, 60, 40, 40, 60$ , and $60$

How many numbers are less than

35

Q. Find mode for grouped data given below

:

X	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$
F	$20$	$10$	$10$	$10$	$40$	$30$

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Number of cars	$0 - 10$	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$	$60 - 70$	$70 - 80$
Frequency	$7$	$9$	$13$	$21$	$12$	$15$	$4$	$12$

Find the median class for the following data given below:Number of cars0−1010−2020−3030−4040−5050−6060−7070−80Frequency7913211215412

The correct option is A 30−40To find the median class:First add the total number of frequencies.Here, f=93=(Totalnumberoffrequency)2=(93)/2=46.5Hence, the value 46.5 lies in the class interval 30-40 from the cummulative frequency table.

Find the median class for the following data given below $:$
Number of cars
$0 - 10$
$10 - 20$
$20 - 30$
$30 - 40$
$40 - 50$
$50 - 60$
$60 - 70$
$70 - 80$
Frequency
$7$
$9$
$13$
$21$
$12$
$15$
$4$
$12$

The correct option is A $30 - 40$
To find the median class $:$
First add the total number of frequencies.
Here, $f = 93$
$= \frac{(T o t a l n u m b e r o f f r e q u e n c y)}{2}$
$= (93) / 2 = 46.5$
Hence, the value 46.5 lies in the class interval 30-40 from the cummulative frequency table.