Find the median class $:$
Marks
$10 - 20$
$20 - 30$
$30 - 40$
$40 - 50$
$50 - 60$
Number of students
$12$
$35$
$15$
$25$
$13$

10 - 20

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50 - 60

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30 - 40

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40 - 50

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Solution

The correct option is B $30 - 40$
To find the median class $:$
First add the total number of frequencies.
Here, $f = 100$
$= \frac{(Total number of frequency)}{2}$
$= \frac{(100)}{2} = 50$
Hence, the value 50 lies in the class interval 30-40 from the cummulative frequency table.

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Similar questions

Q. Find the median of the following distribution

:

Marks	$10 - 20$	$20 - 30$	$30 - 40$	$40 - 50$	$50 - 60$
Number of students	$12$	$35$	$45$	$25$	$13$

The marks obtained by $40$ students of a class are given below :
$80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70,$
$10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80, 90,$ $50, 80,$
$60, 70, 40, 50, 60, 90, 60, 40, 40, 60$ , and $60$

How many numbers are less than

35

Q. The marks obtained by 40 students of a class are given below :

80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70, 10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80,

90, 50, 80, 60, 70, 40, 50, 60, 90, 60, 40, 40, 60

, and

60

How many students obtained marks below

40

Q. The marks obtained by 40 students of a class are given below :

80, 10, 30, 70, 60, 50, 50, 40, 40, 20, 40, 90, 50, 30, 70, 10, 60, 50, 20, 70, 70, 30, 80, 40, 20, 80, 90,

50, 80, 60, 70, 40, 50, 60, 90, 60, 40, 40, 60

, and

60

Construct a frequency distribution table.

Q. Draw a histogram for the following data:

Marks	No. of Students
$10 - 20$	$15$
$20 - 30$	$30$
$30 - 40$	$50$
$40 - 50$	$40$
$50 - 60$	$20$

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Find the median class:Marks10−2020−3030−4040−5050−60Number of students1235152513

The correct option is B 30−40To find the median class:First add the total number of frequencies.Here, f=100 =(Total number of frequency)2 =(100)2=50Hence, the value 50 lies in the class interval 30-40 from the cummulative frequency table.

Find the median class $:$
Marks
$10 - 20$
$20 - 30$
$30 - 40$
$40 - 50$
$50 - 60$
Number of students
$12$
$35$
$15$
$25$
$13$

The correct option is B $30 - 40$
To find the median class $:$
First add the total number of frequencies.
Here, $f = 100$
$= \frac{(Total number of frequency)}{2}$
$= \frac{(100)}{2} = 50$
Hence, the value 50 lies in the class interval 30-40 from the cummulative frequency table.