Find the median for the distribution given below.
Class200−300300−400400−500500−600600−700Number of students3520106
470
First a less than frequency distribution is drawn as shown below.
Wages Frequency Cumulative frequency 200−30033300−40058400−5002028500−6001038600−700644
In the above distribution the total number of observations (labourers) is 44. Hence n = 44.
n2 = 22.
The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median = l + (n2−cf)f× h,
where
l = lower limit of median class,
n = number of observations,
cf = cumulative frequency of class preceding the median class.
f= frequency of median class.
h = class size (assuming class size to be equal).
For the given class,
l = 400
n = 44
cf = 8
f = 20
h = 100
Median = 400 + (442−8)20 × 100
= 400 + (22–8)20× 100
= 400 + 70
= 470
∴ The median is 470.