Find the median for the distribution given below.
Wages200−300300−400400−500500−600600−700Number of labourers3520106
Wages Frequency Cumulative frequency 200−30033300−40058400−5002028500−6001038600−700644
In the above distribution the total number of observations (labourers) is 44. Hence n = 44.
n2 = 22.
The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median=l+(n2−cf)f×h
where
l = lower limit of median class,
n = number of observations,
cf = cumulative frequency of class preceding the median class.
f= frequency of median class.
h = class size (assuming class size to be equal).
For the given distribution,
l = 400
n = 44
cf = 8
f = 20
h = 100
Median=400+(442−8)20×100
=400+(22–8)20×100
=400+70
=470
∴ The median is 470.