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Question

Find the median for the distribution given below.

Wages200300300400400500500600600700Number of labourers3520106


  1. 470

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Solution

The correct option is A 470

Wages Frequency Cumulative frequency 200300333004005840050020285006001038600700644

In the above distribution the total number of observations (labourers) is 44. Hence n = 44.

n2 = 22.

The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.

Median=l+(n2cf)f×h

where

l = lower limit of median class,

n = number of observations,

cf = cumulative frequency of class preceding the median class.

f= frequency of median class.

h = class size (assuming class size to be equal).

For the given distribution,

l = 400

n = 44

cf = 8

f = 20

h = 100

Median=400+(4428)20×100

=400+(228)20×100

=400+70

=470

The median is 470.


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