Find the median for the following data:
Number of animals
$10$
$15$
$25$
$45$
$50$
Average life span
(years)
$2$
$1$
$3$
$4$
$5$

10

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15

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25

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45

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Solution

The correct option is D $45$

Number of Animal

Average life span

Position

$10$

$2$

$2$

$15$

$1$

$3$

$25$

$3$

$6$

$45$

$4$

$10$

$50$

$5$

$15$

Sum of life span $= 2 + 1 + 3 + 4 + 5 = 15 (o d d n u m b e r)$
The Median is at $(\frac{n + 1}{2}) = (\frac{15 + 1}{2}) = 8 p o s i t i o n$
Now, add up the average life span taken as
position $= 2, 2 + 3 = 5, 3 + 3 = 6, 6 + 4 = 10$
$8$ th position comes after $6$ th position but before $10$ th position.
So, Median is $45$

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Similar questions

Class:	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$	$30 - 35$	$35 - 40$	$40 - 45$
Frequency:	$5$	$6$	$15$	$10$	$5$	$4$	$2$	$2$

CI	$0 - 5$	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$	$30 - 35$	$35 - 40$	$40 - 45$	$45 - 50$
$f$	$9$	$13$	$6$	$12$	$9$	$6$	$10$	$15$	$6$	$4$

280

Wage Rate (₹)	5−15	15−25	25−35	35−45	45−55	55−65
Number of Workers	4	6	10	5	3	2

Height (ft)	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$	$25 - 30$
No. of trees	$4$	$3$	$10$	$8$	$5$

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Number of animals	$10$	$15$	$25$	$45$	$50$
Average life span (years)	$2$	$1$	$3$	$4$	$5$