Find the median for the following data.
x $1$ $2$ $3$ $4$ $5$ $6$ $7$ $8$
f $9$ $11$ $5$ $6$ $8$ $1$ $3$ $7$

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Solution

x

f

fx

1

9

9

2

11

22

3

5

15

4

6

24

5

8

40

6

1

6

7

3

21

8

7

56

$N = 50$

Here $N = 50 \Rightarrow \frac{N}{2} = \frac{50}{2} = 25$
Then, frequency greater than $25$ is $40$ where $x$ is $5$
Hence, median $= 5$

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Similar questions

{(\frac{2}{3})}^{5}

{(- \frac{1}{5})}^{4}

$χ$	$1$	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$
$f$	$4$	$6$	$8$	$12$	$17$	$11$	$7$	$6$	$5$	$3$

919829873987649876559876546987654

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

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